面试题答案
一键面试SELECT c.city, COUNT(o.order_id) AS order_count
FROM customers c
JOIN orders o ON c.customer_id = o.customer_id
GROUP BY c.city
ORDER BY order_count DESC, c.city ASC;
SELECT c.city, COUNT(o.order_id) AS order_count
FROM customers c
JOIN orders o ON c.customer_id = o.customer_id
GROUP BY c.city
ORDER BY order_count DESC, c.city ASC;