面试题答案
一键面试function mapAsync<T, U>(array: T[], asyncMapper: (element: T) => Promise<U>): Promise<U[]> {
return Promise.all(array.map(asyncMapper));
}
function mapAsync<T, U>(array: T[], asyncMapper: (element: T) => Promise<U>): Promise<U[]> {
return Promise.all(array.map(asyncMapper));
}